1.

A hydrocarbon with molecular formula C_5H_12on mono chlorination in presence of light gives four compounds A,B,C,D. A is optically inactive and dehydrohalgenation gives E( major) which on ozonolysis gives acetone and acetaldehyde. B is optically active gives on dehydrohalogenation E also gives E as the major product. Further C is optically active while D is optically inactive. Allcompounds A,B,C,D on reduction give 2-methyl butane.Which of the following is the correct structure of A

Answer»

`ClCH_2CH(CH_3)CH_2CH_3`
`(CH_3)_2C(CL)CH_2CH_3`
`(CH_3)_2CHCH(Cl)CH_3`
`(CH_3)_2CHCH_2CH_2Cl`

SOLUTION :


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