1.

A hydrocarbon (X) reacts with Cl_2 giving the substitution product (Y). By the Wurtz reaction 'Y' yields a gaseous hydrocarbon, 'Z' having vapour density = 14. Identify X.

Answer»

`CH_4`
`CH_3 CH_3`
`CH_3 OH`
`CH_3Cl`

Solution :Vapour density of Z = 14.
`implies` MOLECULAR mass of the hydrocarbon (Z) = `2 xx 14 = 28` .
Hence the hydrocarbon is ethane `(C_2 H_6)` .
It can be obtained from METHYL chloride by Wurtz reaction , so the substitution product .Y. is `CH_3 - Cl` and the hydrocarbon .X. is `CH_4` (methane).
`underset("(X)")(CH_(4)) overset(Cl_(2)) (to) CH_(3) underset("(Y)") (C)l overset("Na/ether")("Wurtz reaction") (to) CH_(3) underset("(Z)")(-)CH_3`


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