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A hydrogen atom in a state of binding energy 0.85 eV makes a transtition to a state of excitation energy of 10.2 eV. (i) What is the initial state of hydrogen atom? (ii) What is the final state of hydrogen atom ? (iii) What is the wavelength of the photon emitted ? |
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Answer» Solution :Let `n_(1)` be initial state of electron. Then `E_(1)=-(13.6)/(n_(1)^(2))eV` Here `E_(1)=-0.85eV`, THEREFORE `-0.85=-(13.6)/(n_(1)^(2))` or `n_(1)=4` |
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