1.

A hydrogen atom in ground state absorbs `10.2eV` of energy .The orbital angular momentum of the electron is increases byA. `1.05 xx 10^(-34) J s`B. `2.11 xx 10^(-34) J s`C. `3.16 xx 10^(-34) J s`D. `4.22 xx 10^(-34) J s`

Answer» Correct Answer - A
`- 13.6 - (-10.2) = - 3.4 eV`.
`(-13.6)/(n^(2)) = - 3.4 or n^(2) = (13.6)/(3.4) = 4`
or `n = 2`
Increase in angular momentum `= (2 h)/(2 pi) = (h)/(2 pi) = (h)/(2 pi)`
`= (6.625 xx 10^(-34))/(2 xx 3.14) J s`
`= 1.05 xx 10^(-34) J s`


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