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A hydrogen atom in ground state absorbs `10.2eV` of energy .The orbital angular momentum of the electron is increases byA. `1.05 xx 10^(-34) J s`B. `2.11 xx 10^(-34) J s`C. `3.16 xx 10^(-34) J s`D. `4.22 xx 10^(-34) J s` |
Answer» Correct Answer - A `- 13.6 - (-10.2) = - 3.4 eV`. `(-13.6)/(n^(2)) = - 3.4 or n^(2) = (13.6)/(3.4) = 4` or `n = 2` Increase in angular momentum `= (2 h)/(2 pi) = (h)/(2 pi) = (h)/(2 pi)` `= (6.625 xx 10^(-34))/(2 xx 3.14) J s` `= 1.05 xx 10^(-34) J s` |
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