1.

A hydrogen atom in its ground state absorbs `10.2 eV` of energy. The orbital angular momentum is increased byA. `1.05 xx 10^(-34)J-sec`B. `3.36 xx 10^(-34)J-sec`C. `2.11 xx 10^(-34)J-sec`D. `4.22 xx 10^(-34)J-sec`

Answer» Correct Answer - A
Electron after absorbing `10.2 eV` energy goes to its first excited sate `(n = 2)` from ground state `(n = 1)`.
`:.` Increase in momentum `= (h)/(2pi)`
`= (6.6 xx 10^(-34))/(6.28) = 1.05 xx 10^(-34) j-sec`


Discussion

No Comment Found

Related InterviewSolutions