1.

A hydrogen atom in the ground state absorbe 12.09 eV of energy. The change in the orbital angular momentum of the electron is:

Answer»

`+1.05 XX 10^(-34)Js`
`+2.11 xx 10^(-34)Js`
`-2.11 xx 10^(-34)Js`
`4.22 xx 10^(-34)Js`

SOLUTION :`E_(1)=-13.5eV for n=1`
`E_(3)=-1.51eV for n=3`
`E_(3)-E_(1)=[(1.51-(-13.6)]=12.09eV`
`triangleE=12.08eV for trianglen=3-1=2`
Now `L=n.(h)/(2pi)`
`TRIANGLEL=trianglen.(h)/(2pi)`
here `trianglen=2`
`triangleL=2 .(h)/(2pi)=h/pi`
`triangleL=(6.6 xx 10^(-34))/(3.14)=2.11 xx 10^(-34)Js`


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