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A hydrogen atom in the normal state is locatred at a distance r=2. 5cm from a long straigh condctor carrying a current I= 10A. Find the force acting on the atom. |
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Answer» Solution :The magnetic field at a distacne `R` from a long current carrying wire is mostly tangential and GIVEN by `B_(varphi)=(mu_(0)I)/(2 pi r)=(mu_(0))/(4pi)(2I)/(r )` The force on a magnetic dipole of mement `VEC(mu)` due to this magnetic iels is also tangential and has magnitude `(vec(mu).grad)B_(varphi)` This force is nonvanishing only when the COMPONENT of `vec(mu)` along `vec(r )` non zero. Then `F=mu_(r )(del)/(del r)B_(varphi)= -mu_(r )(mu_(0))/(4pi)(2I)/(r^(2))` Now the maximum value of `mu_(r )=+-mu_(B)` Thus the force is `F_(max)=mu_(B)(mu_(0))/(4pi)(2I)/(r^(2))= 2.97xx10^(-26)N` |
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