A hydrogen atom is in its third excited state. (a) How many spectral lines can be emitted by it before coming to the ground state ? Show these transitions in the energy level diagram. (b) In which of the above transitions will the spectral line of shortest wavelength be emitted ?

A hydrogen atom is in its third excited state. (a) How many spectral

1.	A hydrogen atom is in its third excited state. (a) How many spectral lines can be emitted by it before coming to the ground state ? Show these transitions in the energy level diagram. (b) In which of the above transitions will the spectral line of shortest wavelength be emitted ?
Answer» Solution :(a) The HYDROGEN atom is in its third excited STATE i.e., it is in n= 4 state. Before coming to ground state (n = 1) the total number of spectral lines is `(n(n-1))/2=(4xx3)/2=6`. The transitions corresponding to these six lines are shown in the energy level diagram here. (b) In TRANSITION (4 - 1) energy DIFFERENCE and frequency of emitted radiation is maximum and as a RESULT we get a spectral line of shortest wavelength.

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A hydrogen atom is in its third excited state. (a) How many spectral lines can be emitted by it before coming to the ground state ? Show these transitions in the energy level diagram. (b) In which of the above transitions will the spectral line of shortest wavelength be emitted ?

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