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A hydrogen gas electrode is made by dipping platinum wire is a solution of HCl of pH=10 and by passing hydrogen gas around the platinum wire at one atom prssure. The oxidation potential of the electrode would be |
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Answer» 0.059 V `H^(+)+e^(-)to(1)/(2)H_(2)` `E_(H^(+)//(1)/(2)H_(2))^(@)=E_(H^(+)//(1)/(2)H_(2))^(@)-(0.0591)/(n)"LOG"(p_(H_(2))^(1//2))/([H^(+)])` `=0-(0.0591)/(n)"log"(1)/(10^(-10))=-0.591` `(pH=10" MEANS "[H^(+)]=10^(-10)M)` `therefore`OXIDATION potential`=0.591V` |
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