1.

A hydrogen gas electrode is mae by dipping platinum wire in a solution of HCl of pH=10 and by passing hydrogen gas around the platinum wire at one atm pressure. The oxidation potential of electrode would be

Answer»

1.81 V
0.059V
0.59V
0.118V

Solution :`(1)/(2)H_(2)(g)TOH^(+)+E^(-)`
`E_(O.P.)=E_(O.P.)^(o)-(0.059)/(n)log([H^(+)])/((P_(H_(2)))^(1//2))`
`E_(O.P.)=0-(0.059)/(1)"log"(10^(-10))/((1)^(1//2))(pH=10,[H^(+)]=10^(-10)M)`
`E_(O.P.)=0.59V`


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