A hydrogen like species (atomic number Z) is present in a higher excited state of quantum number n. This excited atom can make a transition to the first excited state by successive emission of two photons of energies 10.20 eV and 17.0 eV respectively. Alternatively, the atom from the same excited state can make a transition to the second excited state by successive emission of two photons of energy 4.25 eV and 5.95 eV respectively. Determine the value of Z. (Given: 27.210.2=2.66 , 601.66≈36 , hcRH=13.6 eV)

A hydrogen like species (atomic number Z) is present in a higher excit

1.	A hydrogen like species (atomic number Z) is present in a higher excited state of quantum number n. This excited atom can make a transition to the first excited state by successive emission of two photons of energies 10.20 eV and 17.0 eV respectively. Alternatively, the atom from the same excited state can make a transition to the second excited state by successive emission of two photons of energy 4.25 eV and 5.95 eV respectively. Determine the value of Z. (Given: 27.210.2=2.66 , 601.66≈36 , hcRH=13.6 eV)
Answer» A hydrogen like species (atomic number $Z$ ) is present in a higher excited state of quantum number $n$ . This excited atom can make a transition to the first excited state by successive emission of two photons of energies $10.20 e V$ and $17.0 e V$ respectively. Alternatively, the atom from the same excited state can make a transition to the second excited state by successive emission of two photons of energy $4.25 e V$ and $5.95 e V$ respectively. Determine the value of $Z$ . $(G i v e n : \frac{27.2}{10.2} = 2.66, \frac{60}{1.66} \approx 36, h c R_{H} = 13.6 e V)$