1.

(A)(i) Arrangethe followingin orderof increasingmolarconductivity 1.Mg[Cr(NH_(3))(CI_(3)) 2. [Cr(NH_(3))CI]_(3) [CoF_(6)1_(2) . 3. [Cr(NH_(3))_(3)Ci_(3)] (ii)Silicon carbideis veryhard. Justifythisstatement. (b)(i)Writethe lawfor thefollowingreactions(a) A reactionthat3//2 orderis x areorderin y. (b)A reactionthat issecond orderin Noand firstorder in Br_(2) (ii) Classifythe followingspeciesintoLewisacidsand lewisbasesand showhowcan actLewisacid //Lewisbase ? (a) OH^(-)ions (b)F^(-) (c _ H^(+) (d ) BCI_(3)

Answer»

Solution :a (i) Thesecomplexcanionisein solutionas
`Mg[Cr(NH_(3)) (CI_(3)) =Mg^(2+)+ [Cr(NH)_(3)) (CI)_(5)]^(2-)`
`[Cr(NH_(3))_(3)Ci_(3)]=` DOESNOT IONIZE
(ii) silicon carbide isveryhard. It iscovalentsolidcontainsthe atomswhichare bound tegetherin thredimensionalnetworkentirely by covalentbonds.So thecovalentnetworkcrystalsiCis veryhardand havehighmeltingpoint.
b (i) `(a) (3)/(2) x + y` (EXCESS ) `to` PRODUCTS
(b) 2 No+ `Br_(2)to` Products(2NOBr)
(ii) (a) `OH^(-)` ions can domateanelectron pairact aslewisbase.
(b) `BCI_(3)` can acceptsan electronpairsinceBoronatomis electrondeficient .Itis a lewisacid.


Discussion

No Comment Found