(a). IF both (A) and (R) are correct and (R) is the correct explanation of (A). (b). If both (A) and (R) are correct but (R) is not the correct explanation of (A). (c). If (A) is correct, but (R) is incorrect. (d). If (A) is incorrect, but (R) is correct. ltbr. (e) if both (A) and (R) are incorrect. Q. Assertion (A): If x " mL of " 0.2 M `H_(2)SO_(4)` solution requires 10 " mL of " 0.24 M KOH solution then x " mL of " 0.1 M `H_(2)SO_(3)` would require 20 " mL of " 0.01 M acidified `K_(2)Cr_(2)O_(7)` solution. Reason (R): `H_(2)SO_(3)` is dibasic acid.

(a). IF both (A) and (R) are correct and (R) is the correct explanatio

1.	(a). IF both (A) and (R) are correct and (R) is the correct explanation of (A). (b). If both (A) and (R) are correct but (R) is not the correct explanation of (A). (c). If (A) is correct, but (R) is incorrect. (d). If (A) is incorrect, but (R) is correct. ltbr. (e) if both (A) and (R) are incorrect. Q. Assertion (A): If x " mL of " 0.2 M `H_(2)SO_(4)` solution requires 10 " mL of " 0.24 M KOH solution then x " mL of " 0.1 M `H_(2)SO_(3)` would require 20 " mL of " 0.01 M acidified `K_(2)Cr_(2)O_(7)` solution. Reason (R): `H_(2)SO_(3)` is dibasic acid.
Answer» Correct Answer - B `H_(2)SO_(4)` vs `KOH` (acid base titration) `m" Eq of "H_(2)SO_(4)=m" Eq of "KOH` `x xx0.2xx2=10xx0.24xx1` `x=6mL` `underset((n=2))(H_(2)SO_(3))vsunderset((n=6))((K_(2)Cr_(2)O_(7))/(H^(o+))` `(SO_(3)^(2-)toSO_(4)^(2-)+2e^(-))(6e^(-)+Cr_(2)O_(7)^(2-)to2Cr^(3+))` `m" Eq of "H_(2)SO_(3)-=m" Eq of "Cr_(2)O_(7)^(2-)` `x xx0.1xx2-=20xx0.01xx6` `x=6 mL` (A) is correct (R) is the correct explanation of (A).

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