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(a) If m is a particle's mass, p is its momentum magnitude, and K is its kinetic energy, show that m=((pc)^(2)-K^(2))/(2Kc^(2)) (b) For low particle speeds, show that the right side of the equation reduces to m. (c ) If a particle has K = 55.0 MeV when p = 121 MeV/c, what is the ratiom//m_(e ) of its mass to the electron mass?

Answer»


ANSWER :`(a) m=[(PC)^(2)-K^(2)]//2Kc^(2); (B) m to 1//mv=m; (c ) 105.6MeV//c^(2)`


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