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| 1. |
(a) In the example 2 the current flowing through the wire is l_((l))=l_(0) sin omegat. What is the flux through the loop at t=(pi)/(2omega)? (b) What is the maximum flux when current l_(t)=l_(0)sin omegat |
| Answer» SOLUTION :(a) `phi_(B)=-(mu_(0)l_(0)l)/(2PI)log_(e).(a+l)/(a), (b) phi_("max")=(mu_(0)l_(0)l)/(2pi)log_(e).(a+l)/(a)` | |