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A inductor of reactance `1 Omega` and a resistor of `2 Omega` are connected in series to the terminals of a 6 V (rms) a.c. source. The power dissipated in the circuit isA. 8WB. 12 WC. 14.4 WD. 18 W |
Answer» Correct Answer - C Given, `X_(L)=1Omega, R=2Omega` `E_(rms) = 6V, P_(av)=?` Average power dissipated in the circuit, `P_(av) = E_(rms) I_(rms) cosphi`...........(i) `I_(rms) = I_(0)/sqrt(2) = E_(rms)/Z` `Z=sqrt(R^(2) + X_(L)^(2))` `=sqrt(4+1) = sqrt(5)` `I_(rms) = 6/sqrt(5) A` `cosphi = R/Z=2/sqrt(5)` `P_(av) = 6 xx 6/sqrt(5) xx 2/sqrt(5)` {from Eq.(i)} `=72/(sqrt(5)sqrt(5))=73/5=14.4` W |
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