1.

A is a king of acid. A reacts with HBr to give B and Bromine. A reacts with Na_(2)CO_(3) to give C and carbon dioxide. Identify A, B and C. Give the reaction.

Answer»

Solution :(i) King of ACID is sulphuric acid (A).
(ii) Sulphuric acid (A) reacts with `HBr` reacts with HBr to give `SO_(2)(B)` and Bromine.
`underset("(A)")(H_(2)SO_(4))+2HBrrarr underset("(SULPHUR DIOXIDE)(B)")(SO_(2))+2H_(2)O+Br_(2)`
(i) Sulphuric acid (A) reacts with `Na_(2)CO_(3)` to give sodium sulphate (C) and `CO_(2)`.
`Na_(2)CO_(3)+underset("(A)")(H_(2)SO_(4))rarr underset("(Sodium sulphate) (C)")(Na_(2)SO_(2))+H_(2)O+CO_(2)`
`|{:(A,"Sulphuric acid",H_(2)SO_(4)),(B,"Sulphur dioxide",SO_(2)),(C,"Sodium sulphate",Na_(2)SO_(4)):}|`


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