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A Jar Was Containing 60 Liters Of Mixture Of Milk And Water In The Ratio 7:5. From This Jar 12 Litres Of Mixtures Was Taken Out And 8 Litres Of Pure Milk Was Added. What Is The Respective Ratio Of Milk And Water In The Mixture After The Final Operation ? |
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Answer» Let n be the MIXTURE quantity of milk = 7/12 × 60 Ltr = 35 Ltr Quantity of water = 5/12 × 60 Ltr. = 25 Ltr 12 Ltr. of mixture removed contains milk = 7/12 × 12 Ltr. = 7 Ltr and water = 5/12 × 12 Ltr = 5 Ltr After adding 8 Ltr of PURE milk, Net milk in the mixture = 35 - 7 + 8 = 36 Ltr. Net water in the mixture = 25 - 5 = 20 Ltr. So the required RATIO of milk and water now = 36/20 = 9/5 Let n be the mixture quantity of milk = 7/12 × 60 Ltr = 35 Ltr Quantity of water = 5/12 × 60 Ltr. = 25 Ltr 12 Ltr. of mixture removed contains milk = 7/12 × 12 Ltr. = 7 Ltr and water = 5/12 × 12 Ltr = 5 Ltr After adding 8 Ltr of pure milk, Net milk in the mixture = 35 - 7 + 8 = 36 Ltr. Net water in the mixture = 25 - 5 = 20 Ltr. So the required ratio of milk and water now = 36/20 = 9/5 |
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