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A jet plane is travelling towards west at a speed of 1800 km/h. What is the voltage difference developed between the ends of the wing having a span of 25 m, if the Earth's magnetic field at the location has a magnitude of 5 xx 10^(-4) and the dip angle is 30^(@)? |
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Answer» Solution :Here speed of jet PLANE `v = 1800 km/h = 1800 xx = 5/18 MS^(-1) = 500 ms^(-1)`, length between the ends of the wing of plane `I = 25 m, B_(E) = 5 xx10^(4) + T` and dip angle `delta =30^(@)` `THEREFORE` Vertical component of Earth.s magnetic field `B_(V) = B_(E). sin delta = 5 xx 10^(-4) xx sin 30^(@) = 2.5 xx 10^(-4) ` `therefore` Voltage DIFFERENCE developed `V = B_(V) .l.v1 = 2.5 xx 10^(-4) xx 25 xx 500 = 3.125 V = 3.1 V. |
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