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A juggler keeps n balls going with one hand, so that at any instant, (n - 1) balls are in air and one ball in the hand. If each ball rises to a height of x metres, the time for each ball to stay in his hand isA. `1/n -1((sqrt 2x)/g)`B. `2/n - 1((sqrt 2x)/g)`C. `2/n((sqrt 2x)/ g)`D. `1/n((sqrt 2x)/ g)` |
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Answer» Correct Answer - (b) Let u be the initial velocity of the ball while going upwards. The final velocity of the ball at height x is, v = 0. So u = `sqrt(2gx)` Time of flight, `T = (2u)/g = 2/g sqrt(2gx) = 2 sqrt(2x)/g` During time T, (n -1) balls will be in air and one ball will be in hand. So time for one ball in hand `T /(n - 1) = 2 sqrt(2x)/g(n - 1) = 2 / n - 1 ((sqrt 2x)/g)` |
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