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A train starts from rest with constant acceleration `a=1 m//s^(2)` A passenger at a distance S from the train runs at this maximum velocity of `10 m//s` to catch the train at the same moment at which the train starts. Find the critical distance `S_(c)` for which passenger will take the ten seconds time to catch the trainA. 50 mB. 35 mC. 30 mD. 25 m |
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Answer» Correct Answer - A The critical distance `S_(c)` for which passenger will take the ten seconds time to catch the train is given by `S_(C)=(v_(P)^(2))/(2a_(1))` The time is 10 seconds if `V_(P)^(2)-2a_(1)S=0` `S_(C)=(V_(P)^(2))/(2a_(t))=((10)^(2))/(2(1))=50m` |
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