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A train starts from rest with constant acceleration `a=1 m//s^(2)` A passenger at a distance S from the train runs at this maximum velocity of `10 m//s` to catch the train at the same moment at which the train starts. Find the speed of the train when the passenger catches it for the critical distance:A. `8 m//s`B. `10 m//s`C. `12 m//s`D. `15 m//s` |
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Answer» Correct Answer - B For critical distance, passenger catches the train in time `t=(V_(P))/(a_(t))` So, required velocity of train `a_(t).t` `=a_(t)((v_(P))/(a_(t)))=V_(P)//2 =10 m//sec` |
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