1.

A kite flying at a height 'h' mts has ''x'' meters of string paid out at a seconds. If the kite moves horizontally with constant v mts/sec. Then the rate at which the string is paid out is

Answer»

`(SQRT(X^(2)-H^(2)))/(v)mt//sec`
`sqrt(x^(2)-h^(2))mt//sec`
`(vsqrt(x^(2)-h^(2)))/(x)mt//sec`
`(sqrt(x^(2)-h^(2)))/(h)mt//sec`

ANSWER :C


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