1.

A L-C-R circuit connected to an A.C. source of frequency f. If current in phase leads by 45^@ then voltage, the capacitance of capacitor ……….

Answer»

`1/(2pif(2pifL-R))`
`1/(2pif(2pifL+R))`
`1/(PIF(2pifL-R))`
`1/(pif(2pifL+R))`

SOLUTION :`tan DELTA=(omegaL-1/(omegaC))/R`
`therefore tan 45^@ =(omegaL-1/(omegaC))/R`
`therefore R=omegaL-1/(omegaC)`
`therefore 1/(omegaC)=omegaL-R`
`therefore omegaC=1/(omegaL-R)`
`therefore C=1/(omega(omegaL-R))`
`therefore C=1/(2pif(2pifL-R))`


Discussion

No Comment Found

Related InterviewSolutions