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A lab assistant prepared a solution by adding a calculated quantity of HCl gas 25^@C to get a solution with [H_3O^+]=4 times 10^-5M. Is the solution neutral (or) acidic (or) basic. |
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Answer» SOLUTION :`[H_3O^+]=4 TIMES 10^-5 M` `pH=-log_10[H_3O^+]` `pH=-log_10[4 times 10^-5]` `pH=-log_10[4]-log_10[10^-5]` `pH=-0.6020-(-5)=-0.6020+5` `pH=4.398` |
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