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a ladder is 25m long reaches a window of a building 20m above the ground determine the distance of the foot of the ladder from this building |
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Answer» Length of ladder = 25 mA ladder REACHES a window of a building 20 m above the ground.Refer the attached figureAB = 20AC = 25We are supposed to FIND the distance of the FOOT of the ladder from the building i.e. BCHypotenuse^2=Perpendicular^2+BASE^2Hypotenuse 2 =Perpendicular 2 +Base 2 AC^2=AB^2+BC^2AC 2 =AB 2 +BC 2 25^2=20^2+BC^225 2 =20 2 +BC 2 \sqrt{25^2-20^2}=BC 25 2 −20 2 =BC15=BC15=BCHence the distance of the foot of the ladder from the building is 15 m |
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