A lamp consumes only 50% of maximum power applied in an A.C. circuit. What will be the phase difference between applied voltage and circuit current ?

A lamp consumes only 50% of maximum power applied in an A.C. circuit.

1.	A lamp consumes only 50% of maximum power applied in an A.C. circuit. What will be the phase difference between applied voltage and circuit current ?
Answer» `pi/6` RAD `pi/3` rad `pi/4` rad `pi/2` rad Solution :`P=P_m cos DELTA` `THEREFORE cos delta =P/P_m =P_(m//2)/P_m=1/2` `therefore delta = pi/3` RADIAN

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A lamp consumes only 50% of maximum power applied in an A.C. circuit. What will be the phase difference between applied voltage and circuit current ?

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