1.

A large cylinder for storing compressed gas has a volume of 1.5 f t^(3). If the gas is stored under a pressure of 150 atm at 300 K, how many moles of the gas cylinder ? (1 f t^(2) = 28.32 "litre")

Answer»

Solution :pV = nRT
`n = (150 XX (1.5 xx 28.32))/(0.0821 xx 300)`
`= 258.70` moles.
(R = 0.0821 lit. atm/K/mole)
Weight of oxygen = moles `xx` MOL. Weight
`= 258.70 xx 32`
=8278.40 g.


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