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A lead piece of mass `25 g` gives out `1200` calories of heat when it is cooled from `90^@ C` to `10^@ C`. What is its (i) specific heat (ii) thermal capacity (iii) water equivalent. |
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Answer» Mass of lead piece `(m) = 25 g = 0.025 kg` Heat energy given out `(dQ) = 1200 xx 4.2 J` (i) specific heat `S = (1)/(m)(dQ)/(d theta)` =`(1)/(0.025) xx (1200 xx 4.2)/(80) = 2520 JKg^(-1) K^(-1)` (ii) Thermal capacity `= mS = 0.025 xx 2520 = 63 J//K` (iii) Water equivalent `(63)/(4200) Kg = 0.015 Kg`. |
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