1.

A lead sphere of mass m falls in a viscous liquid with a terminal velocity v0. Another lead sphere of mass S m through the same liquid will fall with the terminal velocity:

Answer»

`v_(0)`
`4v_(0)`
`8v_(0)`
`64v_(0)`

Solution :Since mass is 8 times the first SPHERE
`therefore` VOLUME is also 8 times the first sphere or radius is 2 times the first sphere.
As TERMINAL velocity `V oo r^(2)`.
`therefore` Velocity becomes 4 times`rArrv^(2)=4v_(0)`
Thus correct choice is (b)
Hence the correct choice is (c).


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