1.

A leftis ascending with an acceleration equal to g/3. What will be the time period of the simple pendulum suspended from its ceiling if its time period in stationary lift is T ?

Answer»

`T//2`
`(sqrt(3//4))T`
`T//4`
`(sqrt(3//2))T`.

SOLUTION :`T=2pi sqrt((l)/(G))` and `T.=2pi sqrt((l)/(g+a))`
`implies""T.=2pi sqrt((l)/(g+(g)/(3)))`
`:.""T.=2pi sqrt((3L)/(4g))`
`implies""T.=sqrt((3)/(4)).T.`
Correct CHOICE is (B)`.


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