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InterviewSolution
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A lens if placed between a source of light and a wall. It forms images of area` A_(1)` and `A_(2)` on the wall for its two different positions. The area of the source or light isA. `(A_(1)+A_(2))/(2)`B. `[(1)/A_(1)+(1)/A_(2)]^(-1)`C. `sqrt(A_(1)A_(2))`D. `[(sqrt(A_(1))+sqrt(A_(2)))/(2)]^(2)` |
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Answer» Correct Answer - C `m_(1)=(A_(1))/(O)` and `m_(2)=(A_(2))/(O)` `impliesm_(1)m_(2)=(A_(1)A_(2))/(O_(2))` Also it can be proved that `m_(1)m_(2)=1` So `O=sqrt(A_(1)A_(2))` |
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