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A letter of English alphabets is chosen at random. Determine the probability that the letter is a consonant. |
Answer» We know that, in English alphabets, there are (5 vowels + 21 consonants) = 26 letters. So, total number of outcomes in English alphabets is,n(S) = 26 Let E = Event of choosing an English alphabet, which is a consonant = {b, c, d, f, g, h, j, k, l, m, n, p, q, r, s t, v, w, x, y, z} ∴ n(E) = 21 Hence, required probability = n(E)/n(S) = 21/26 |
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