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A light bulb is rated at 100 W for a 220 V ac supply . The resistance of the bulb isA. `284 Omega`B. `384 Omega`C. `484 Omega`D. `584 Omega` |
Answer» Correct Answer - C Here, `P = 100 W, V_("rms")=220 V` Resistance of the bulb is `R=(V_("rms")^(2))/(P)=((220)^(2))/(100)=484 Omega` |
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