1.

A light bulb is rated at 100W for a 220 V supply. Find The resistance of the bulb,

Answer»

SOLUTION :We are given P = 100 W and V = 220 V. The resistance of the BULB is
`R = (V^(2))/(P)=((220V)^(2))/(100 W)=484 OMEGA`


Discussion

No Comment Found

Related InterviewSolutions