1.

A light having wavelength 300 nm falls on a metal surface work function of metal is 2.54 eV. What is stopping potential ?

Answer»

1.4 V
2.59 V
1.60 V
1.29 V

Solution :`eV_(0) = H UPSILON - W_(0) = 2eV - 0.6 eV = 1.4 eV`
`therefore""V_(0) = (1.4 eV)/(e) = 1.4 V1`


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