1.

A light of 6000 Å is used to produce interference pattern.The observed fringe widht is 0.12 mm. The angle between twointerfering wave trains is :

Answer»

`2 xx 10^(-3)` radian
`3 xx 10^(-3)` radian
`4 xx 10^(-3)` radian
`5 xx 10^(-3)` radian.

Solution :Here `beta = (LAMBDA D)/(d)`
ANGLE `theta` between two waves train is
`theta = (d)/(D) = (lambda)/(beta)`

or `theta = (6000 xx 10^(-10))/(0.12 xx 10^(-3))`
` = 5 xx 10^(-3)` radian.


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