1.

A light of wavelength 5500 Å falls normally on a slit of width 22 xx 10^(-5) cm. Calculate the angular position of the first two minima on either side of the central maxima :

Answer»

`14^(@) 29', 30^(@)`
`6.14^(@), 12.6^(@)`
`12.6^(@), 24.2^(@)`
NONE of these.

Solution :Position of MIN. Is GIVEN by
`d sin theta = n lambda`
`sin theta = (n lambda)/(d) , n = 1`
`sin theta_(1) = (lambda)/(d) = (5500 xx 10^(-8))/(22 xx 10^(-5)) = 1/4`
Then `theta_(1) = 14^(@).29.`
For second order n - 2
`sin theta_(2) = (2 lambda)/(d) = 1/2`
Then `theta_(2) = 30^(@)`


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