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A light of wavelength 5500 Å falls normally on a slit of width 22 xx 10^(-5) cm. Calculate the angular position of the first two minima on either side of the central maxima : |
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Answer» `14^(@) 29', 30^(@)` `d sin theta = n lambda` `sin theta = (n lambda)/(d) , n = 1` `sin theta_(1) = (lambda)/(d) = (5500 xx 10^(-8))/(22 xx 10^(-5)) = 1/4` Then `theta_(1) = 14^(@).29.` For second order n - 2 `sin theta_(2) = (2 lambda)/(d) = 1/2` Then `theta_(2) = 30^(@)` |
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