1.

A light ray incident along vector 2hati+4hatj+sqrt(5)hatk strikes in the x-z from medium of refractive index sqrt(3) and enters into medium II of refractive index is mu_(2). The value of mu_(2) for which the value of angle of refraction becomes 90^(@) is

Answer»

`(4sqrt(3))/5`
`(3sqrt(3))/5`
`(2sqrt(3))/5`
`(sqrt(3))/5`

Solution :`sintheta_(C)=mu_(2)//mu_(1)`
`1-cos^(2)theta_(C)=((mu_(2))/(mu_(1)))^(2)`
`1-(hatn.hatp)^(2)=((mu_(2))/(mu_(1)))^(2)`
`1-[4/(sqrt(25))]^(2)=((mu_(2))/(mu_(1)))^(2)IMPLIES(mu_(2))/(mu_(1))=3/5`
`implies mu_(2)=(3sqrt(3))/5`


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