1.

A light wave, travelling at 3xx10^(8)m//s has a frequency of 6xx10^(15) Hz. What is its wavelength?

Answer»

`5xx10^(-8)m`
`2xx10^(-7)m`
`5xx10^(-7)m`
`5xx10^(-6)m`

Solution :We USE the EQUATION that RELATES wavelength, FREQUENCY, and wave speed
`lamdaf=vimplies lamda=(c)/(f)=(3xx10^(8)m//s)/(6xx10^(15)Hz)=0.5xx10^(-7)m=5xx10^(-8)m`.


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