A light with an electric field E = 165 [sin (22 xx 10^(15)t) + sin(pi lt 10^(14)t) Vm^(-1) where t is in seconds, falls on a metal of work function 2 eV. The maximum kinetic energy of the photoelectron is (h=4.14 xx 10^(15)eV.S)

A light with an electric field E = 165 [sin (22 xx 10^(15)t) + sin(pi

1.	A light with an electric field E = 165 [sin (22 xx 10^(15)t) + sin(pi lt 10^(14)t) Vm^(-1) where t is in seconds, falls on a metal of work function 2 eV. The maximum kinetic energy of the photoelectron is (h=4.14 xx 10^(15)eV.S)
Answer» 1.8eV 2.14eV 2.34eV 4.41eV Solution :Maximum K.E. of PHOTOELECTRON, `E_(k)=hv-W, " where work FUNCTION W=2eV"` `E_(k)=4.41 XX 10^(-15) 10^(15)-2=2.14eV`

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A light with an electric field E = 165 [sin (22 xx 10^(15)t) + sin(pi lt 10^(14)t) Vm^(-1) where t is in seconds, falls on a metal of work function 2 eV. The maximum kinetic energy of the photoelectron is (h=4.14 xx 10^(15)eV.S)

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