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A line OA length r starts from its initial position OX and traces an angle AOB = alpha in the anticlockwise direction. It then traces back in the clockwise direction an angle BOC = 3 theta ( where alpha gt 3 theta ) . L is the foot of the the perpendicular from C on OA. (sin^3 theta)/(CL) = (cos^3 theta)/(OL ) = 1 (2rsin alpha)/(1+2rcos alpha)is equal to |
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Answer» `TAN^2 THETA` |
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