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A line OA of length r starts from its initial position OX and traces an angle AOB = alpha in the anticlockwise direction. It then traces back in the clockwise direction an angle BOC = 3 theta (where alpha gt 3 theta). L is the foot of the perpendicular from C on OA. (sin^(3)theta)/(CL) = (cos^(3) theta)/(OL) = 1 (2r^(2) - 1)/(r) is equal to |
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Answer» `sin alpha` |
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