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A line through A (-5,-4)with slopetantheta " meets the line " x+3y+2=0, 2x+y+4=0, x-y-5=0 at B,C,Drespectivelly, such that (15/AB)^2+(10/AC)^2 =(6/AD)^2 then |
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Answer» `15/AB=costheta+3sintheta` |
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