1.

A line through A (-5,-4)with slopetantheta " meets the line " x+3y+2=0, 2x+y+4=0, x-y-5=0 at B,C,Drespectivelly, such that (15/AB)^2+(10/AC)^2 =(6/AD)^2 then

Answer»

`15/AB=costheta+3sintheta`
`10/AC=2costheta+sintheta`
`6/AD= costheta-sintheta`
slope of the LINE `-(2)/3`

Answer :A::B::C::D


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