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A linear harmonic oscillator has a total mechanical energy of `200 J`. Potential energy of it at mean position is `50J`. Find (i) the maximum kinetic energy, (ii)the minimum potential energy,(iii) the potential energy at extreme positions. |
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Answer» At mean position , potential energy is minimum and kinetic energy is maximum . Hence. `U_(min) = 50 J` (at mean position) And ` K_(max) = E - U_(min) = 200 - 50` `K_(max) = 150 J` (at mean position) At exterme positions, kinetic energy is zero and potential energy is maximum `:. U_(max) = E` `= 200 J` (at exterme position) |
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