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A linear harmonic oscillator of force constant `2 xx 10^(6)N//m` and amplitude `0.01 m` has a total mechanical energy of `160 J`. ItsA. maximum potential energy is 160 JB. maximum potential energy is 100 JC. minimum potential energy is zeroD. minimum potential energy is 100 J |
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Answer» Correct Answer - A (a)`(1)/(2)kA^(2)=(1)/(2)xx2xx10^(6)xx(0.01)^(2)=100 J` At mean position , U=60 J and K=100 J At extreme positions , U=160 J and K=0 |
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