1.

A linear harmonic oscillator of force constant `2 xx 10^(6)N//m` and amplitude `0.01 m` has a total mechanical energy of `160 J`. ItsA. maximum potential energy is 160 JB. maximum potential energy is 100 JC. minimum potential energy is zeroD. minimum potential energy is 100 J

Answer» Correct Answer - A
(a)`(1)/(2)kA^(2)=(1)/(2)xx2xx10^(6)xx(0.01)^(2)=100 J`
At mean position ,
U=60 J and K=100 J
At extreme positions ,
U=160 J and K=0


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