1.

A linear harmonic oscillator of force constant `2 xx 10^6 N//m` and amplitude (0.01 m) has a total mechanical energy of (160 J). Its.A. Maximum potential energy is 100 JB. Maximum K.E. is 100 JC. Maximum P.E. is 40 JD. Minimum P.E. is zero

Answer» Correct Answer - B
Maximum kinetic energy =`1/2 Ka^(2)=100 J`


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