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A linear object of size 1.5 cm is placed at 10 cm from a lens of focal length 20 cm. The optic centre of lens and the object are displaced are displaced a distance Delta. Thed magnification of the image formed is m. (Take optic centre of origin). The coordinates of image of A and B are (x_(1),y_(1)) and (x_(2),y_(2)) respectively then |
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Answer» `(x_(1),y_(1)) = (-20 CM, -2 cm)`  `1/v - 1/u = 1/f , 1/v = 1/20 - 1/10 = (-1)/(20) rArr v= - 20 cm` Magnification, `m = (v)/(u) = (-20)/(-10) = 2` Heightof image `= 1.5 xx 2 = 3 cm` The `y_(1)` coordinate of a point A on the image will be ` y_(1) = (-0.5) xx 2 = - 1 cm` The `y_(2)` coordinate of a point B on the image will be `y_(2) = 1 xx 2 = 2 cm` |
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