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A linear object of size 1.5cm placed at 10cm from a lens of focal length 20cm. The optic centre of lens and the object are displaced a distance Delta. The magnification of the image formed is m (Take optic centre as origin). The coordinates of image of A and B are (x_(1),y_(1)) and (x_(2),y_(2)) respectively. Then |
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Answer» `(x_(1),y_(1))=(-20cm, -1cm)` `(1)/(u)-(1)/(V)=(1)/(f)` `(1)/(v)=(1)/(20)-(1)/(20)=(1-2)/(20)=(-1)/(20)rArrv=-20cm` Magnification `m=(v)/(u)=(-20)/(-10)=2` Height of IMAGE `=1.5xx2=3cm` The `y_(1)` coordinate of a point A on the image will be `y_(1)=(0.5)xx2=-1cm` The `y_(2)` coordinate of a ppoint B on the image will be `y_(2)=1xx2=2cm` 
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