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A linearly polarized electromagnetic wave given as vec(E )=E_(0)cos(kz-omega t)hat(i) is incident normally on a perfectly reflecting infinite wall at z = a. Assuming that the material of the wall is optically inactive, the reflected wave will be given as |
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Answer» `vec(E )_(r )=E_(0)(kz-omega t)hat(i)` `THEREFORE` Reflected wave `vec(E )=E_(0)cos {kz - omega t}hat(i)` Reflected wave propagates in negative x - direction hence reflected wave `vec(E )_(r )=-E_(0)cos{K(-Z)-omega t+pi}hat(i)` `=-E_(0)cos{-(kz+omega t)+pi}hat(i)` `=+E_(0)cos(kz+omega)hat(i)` `[because cos(-theta)=cos theta " and " cos(pi+theta)=-cos theta]` `therefore vec(E )_(r )=E_(0)cos(kz+omega t)hat(i)` |
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